How to Make Auto Cut Off Circuit

Hii friend,

Today I am going to make a circuit of auto cut off using 2N2222A transistor.This circuit is very simple.

Let's get started,

Components required -

(1.) Battery - 9V x1

(2.) Transistor - 2N2222A x1

(3.) Resistor - 2.2K x2

(4.) LED - 9V

(5.) Battery clipper

(6.) Diode - 1N4007 x1

Solder 2.2K resistor to Base and Emmiter pin of the transistor.

Next we have to solder +ve of the diode to base pin of transistor and

also solder a 2.2K resistor to the base pin of transistor as solder in the picture.

Here this LED is not of 9V.Therefore I connected a 220 ohm resistor to its +ve pin as you can see in the picture.

Next solder +ve wire of LED to 2.2K resistor which is connected to the base pin of transistor and

also connect -ve wire of LED to collector pin of the transistor as you can see in the picture.

Now we have to solder battery clipper wire to the circuit.

Solder +ve wire of battery clipper to +ve of LED and

-ve of battery clipper to emmiter pin of the transistor.

As you can see in the picture when I give power supply then LED is start glowing.

Now connect charger wire to the circuit.

As you can see in the picture when I give power supply for charging then LED gone turn off automatically.

~ When light will be available then LED will not be glow and as light will not be available then LED will start glowing automatically.

This type we can make auto cut off circuit using 2N2222A transistor.

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Thank you